Does anyone know how to do this math word problem?

To determine the number of deer in a game preserve a conservationist catches 329 deer, tags them and lets them loose. Later, 624 deer are caught; 208 of them are tagged. How many deer are in the perserve?

Thank you !!

329*624/208 = 987 are in total.

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9 Responses to Does anyone know how to do this math word problem?

  1. apcalculushelp says:

    Ok.
    Number of deer tagged: 329
    624 caught, and 208 tagged.
    So the number of deer that were tagged, but not caught, has to be: 624-208 = 416.
    SORRY. I WAS DUMB! Ok.EDIT:
    416 were caught but not tagged. SO, you have 416 + the original 329.
    416+329=745.
    745 DEER SORRY!
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  2. sv says:

    329*624/208 = 987 are in total.
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  3. Ivanhoe Fats says:

    about 1000 deer

    see my answer to your previous asking of this question
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  4. reddjoker1 says:

    JUST ADD THE 329 AND THE 208 GIVE YOU 537, THE ORTHER DEER HAVE BEEN TAGED
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  5. sfroggy5 says:

    Idk, at least 745

    624 – 208 that were tagged = 416 not tagged

    416 not tagged + 329 tagged = 745

    there has to be more, there is no way that they caught all the untagged ones.
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  6. dixie123456789 says:

    I think 624
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  7. gayu says:

    624
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  8. Helper says:

    the answer is 745
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  9. teddy boy says:

    329 deers = number of deers caught and tagged the first time

    208 deers = number of deers re-caught with tags our of 624 deers caught the second time.

    Find: x = number of deers in the preserve

    Solution:
    No. of Deers Caught the First Time andTagged + No. of Deers Caught without Tags Second Time + No. Deers Still Uncaught without Tag = x
    329 + (624 – 208) + still uncaught without tag = x
    329 + 416 + still uncaught without tag = x
    745 + still uncaught without tag = x

    AT LEAST, there are 745 deers in the preserve

    teddy boy
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